document.write( "Question 78825: Factor completely.
\n" ); document.write( " 12x^3 – 3xy^2
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\n" ); document.write( "12x(x – 3y)(x – y)\r
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Algebra.Com's Answer #56575 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
12x^3 – 3xy^2
\n" ); document.write( "This is my answer is it right?
\n" ); document.write( "12x(x – 3y)(x – y)
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\n" ); document.write( "No, you can factor out 3x, not 12x
\n" ); document.write( "3x(4x^2 - y^2)
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\n" ); document.write( "(4x^2 - y^2) is the difference of squares so you have:
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\n" ); document.write( "3x(2x - y)(2x + y)
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\n" ); document.write( "you can check it by
\n" ); document.write( "FOILing (2x - y) (2x + y) to
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\n" ); document.write( "Then
\n" ); document.write( "3x*(4x^2 - y^2) = 12x^3 - 3xy^2, the original expression
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\n" ); document.write( "Remember what is outside of the brackets, affects everything inside the brackets
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