document.write( "Question 931655: The length of a rectangle is 6 ft. Greater than its width.the area is 832 sq/ft. Find its dimensions \n" ); document.write( "
Algebra.Com's Answer #565712 by Stitch(470)\"\" \"About 
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Equation 1: \"A+=+L+%2A+W\" The area of a rectangle
\n" ); document.write( "Equation 2: \"L+=+W+%2B+6\"
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\n" ); document.write( "We are given A = 832.
\n" ); document.write( "Since equation 2 is already solved for L, plug (W+6) into equation 1 for L
\n" ); document.write( "Equation 1: \"A+=+L+%2A+W\"
\n" ); document.write( "\"832+=+%28W%2B6%29+%2A+W\"
\n" ); document.write( "Multiply the W through.
\n" ); document.write( "\"832+=+W%5E2+%2B+6W\"
\n" ); document.write( "Set the equation equal to zero by subtracting 832 from both sides.
\n" ); document.write( "\"0+=+W%5E2+%2B+6W+-+832\"
\n" ); document.write( "Now we can use the quadratic equation
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aW%5E2%2BbW%2Bc=0\" (in our case \"1W%5E2%2B6W%2B-832+=+0\") has the following solutons:
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\n" ); document.write( " \"W%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%286%29%5E2-4%2A1%2A-832=3364\".
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\n" ); document.write( " Discriminant d=3364 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-6%2B-sqrt%28+3364+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"W%5B1%5D+=+%28-%286%29%2Bsqrt%28+3364+%29%29%2F2%5C1+=+26\"
\n" ); document.write( " \"W%5B2%5D+=+%28-%286%29-sqrt%28+3364+%29%29%2F2%5C1+=+-32\"
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\n" ); document.write( " Quadratic expression \"1W%5E2%2B6W%2B-832\" can be factored:
\n" ); document.write( " \"1W%5E2%2B6W%2B-832+=+1%28W-26%29%2A%28W--32%29\"
\n" ); document.write( " Again, the answer is: 26, -32.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B6%2Ax%2B-832+%29\"

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\n" ); document.write( "Since we can only have a positive distance, 26ft is W.\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28W+=+26ft%29\"
\n" ); document.write( "Now plug 26 into equation 2 for W
\n" ); document.write( "Equation 2: \"L+=+W+%2B+6\"
\n" ); document.write( "\"L+=+26+%2B+6\"
\n" ); document.write( "\"highlight%28L+=+32ft%29\"
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