document.write( "Question 931655: The length of a rectangle is 6 ft. Greater than its width.the area is 832 sq/ft. Find its dimensions \n" ); document.write( "
Algebra.Com's Answer #565712 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "---------------------------- \n" ); document.write( "We are given A = 832. \n" ); document.write( "Since equation 2 is already solved for L, plug (W+6) into equation 1 for L \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( "Multiply the W through. \n" ); document.write( " \n" ); document.write( "Set the equation equal to zero by subtracting 832 from both sides. \n" ); document.write( " \n" ); document.write( "Now we can use the quadratic equation \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------------------------- \n" ); document.write( "Since we can only have a positive distance, 26ft is W.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Now plug 26 into equation 2 for W \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( " |