document.write( "Question 78842: Condense each logarithm. (express as a single log)pick a right chose
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Algebra.Com's Answer #56567 by Edwin McCravy(20059)\"\" \"About 
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document.write( "Condense each logarithm. (express\r\n" );
document.write( "as a single log) \r\n" );
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document.write( "log 12 + 4 log 2 - log 3 \r\n" );
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document.write( "a. log 32 \r\n" );
document.write( "b. log 64 \r\n" );
document.write( "c. log 2 \r\n" );
document.write( "d. log 3 \r\n" );
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document.write( "log 12 + 4 log 2 - log 3\r\n" );
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document.write( "In the second term, the coefficient 4 \r\n" );
document.write( "moves up and becomes an exponent of \r\n" );
document.write( "the 2\r\n" );
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document.write( "log 12 + log 24 - log 3\r\n" );
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document.write( "Write the 24 as 16:\r\n" );
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document.write( "log 12 + log 16 - log 3\r\n" );
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document.write( "When you take log out of a sum (addition),\r\n" );
document.write( "the sum (addition) becomes a product \r\n" );
document.write( "(multiplication).  So take log out of the\r\n" );
document.write( "first two terms and change the + to × :\r\n" );
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document.write( "     log(12×16) - log 3\r\n" );
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document.write( "Replace the 12×16 by 192 \r\n" );
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document.write( "        log 192 - log 3\r\n" );
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document.write( "When you take \"log\" out of a difference\r\n" );
document.write( "(subtraction), the difference (subtraction)\r\n" );
document.write( "becomes a quotient (division).  So take the \r\n" );
document.write( "\"log\" out of those two terms and change\r\n" );
document.write( "the - to ÷ :\r\n" );
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document.write( "        log (192÷3)\r\n" );
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document.write( "Replace 192÷3 by 64\r\n" );
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document.write( "        log 64\r\n" );
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document.write( "Choice (b)\r\n" );
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document.write( "Edwin
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