document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=931588>Question 931588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> store sells bluegrass seed that is worth $6 per pound and ryegrass seed that is worth $3 per pound.  How much of each should be mixed to obtain 80 pounds of a blend that is worth $5 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565649 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> store sells bluegrass seed that is worth $6 per pound and ryegrass seed that is worth $3 per pound. How much of each should be mixed to obtain 80 pounds of a blend that is worth $5 per pound?<BR>\n" );
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document.write( "Weight Equation:: b + r = 80 lbs<BR>\n" );
document.write( "Value Equation::: 6b + 3r = 5*80 dollars<BR>\n" );
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document.write( "Modify::<BR>\n" );
document.write( "6b + 6r = 6*80<BR>\n" );
document.write( "6b + 3r = 5*80<BR>\n" );
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document.write( "3r = 80<BR>\n" );
document.write( "r = 80/3 = 26 2/3 lbs (amt. of rye seed needed)<BR>\n" );
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document.write( "Solve for \"b\"::<BR>\n" );
document.write( "b + (80/3) = 80<BR>\n" );
document.write( "b = 53 1/3 lb (amt. of bluegrass seed needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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