document.write( "Question 931592: solve algebraically\r
\n" );
document.write( "\n" );
document.write( "4x^2+y^2=64
\n" );
document.write( "x^2+y^2=52 \n" );
document.write( "
Algebra.Com's Answer #565636 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! 4x^2+y^2=64 \n" ); document.write( "-1(x^2+y^2=52) \n" ); document.write( "3x^2 = 12 \n" ); document.write( "x^2 = 4 \n" ); document.write( "x = ± 2 \n" ); document.write( "y = √48 = ±4√3 \n" ); document.write( "....... \n" ); document.write( "(-2,4√3), (-2,-4√3), (2,4√3), (2,-4√3), \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |