document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78836>Question 78836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for p\r<BR>\n" );
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document.write( "4p^2-12p-91=0\r<BR>\n" );
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document.write( "our class is solving these type equations using the quadratic formula:<BR>\n" );
document.write( "(-b +and- square root of b^2-4ac)/2a\r<BR>\n" );
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document.write( "so it would help a lot if you showed how to do it by plugging it into that formula. \r<BR>\n" );
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document.write( "i tried the problem once and got no real solution and then plugged it in again  and got 6.5,-3.5. and i don't know which one's right because my notes say that the a has to equal 1... but im not sure if thats right or not </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56562 by </B><A HREF=/tutors/aboutme.mpl?userid=mathdoc314><B>mathdoc314(58)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathdoc314><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "If you wanted a to be equal to 1 for some reason, <BR>\n" );
document.write( "you could divide everything through by a.  To use the quadratic formula you do not have to have a=1.\r<BR>\n" );
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document.write( "4p^2-12p-91=0<BR>\n" );
document.write( "p^2 - 3p - 91/4 = 0\r<BR>\n" );
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document.write( "a=4, b=-12, c=-91\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+%2812+%2B-+sqrt%28+144%2B16%2A91+%29%29%2F%282%2A4%29+ ALIGN=MIDDLE  ALT=\"p+=+%2812+%2B-+sqrt%28+144%2B16%2A91+%29%29%2F%282%2A4%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+%2812+%2B-+sqrt%28+1600+%29%29%2F8+ ALIGN=MIDDLE  ALT=\"p+=+%2812+%2B-+sqrt%28+1600+%29%29%2F8+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+%2812+%2B-+40%29%2F8+ ALIGN=MIDDLE  ALT=\"p+=+%2812+%2B-+40%29%2F8+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+52%2F8+or+-28%2F8+ ALIGN=MIDDLE  ALT=\"p+=+52%2F8+or+-28%2F8+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+6.5+or+-3.5+ ALIGN=MIDDLE  ALT=\"p+=+6.5+or+-3.5+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can plug the values into the original equation (or equivalent) to check:\r<BR>\n" );
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document.write( "(-3.5)^2 - 3(-3.5) - 91/4 = 49/4 + 42/4 - 91/4 = 0\r<BR>\n" );
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document.write( "(6.5)^2 - 3(6.5) - 91/4 = 169/4 - 78/4 - 91/4 = 0\r<BR>\n" );
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document.write( " </SPAN>\n" );
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