document.write( "Question 931507: 1/3, 8/3, 27/3, 64/3, 125/3 identify the sequence \n" ); document.write( "
Algebra.Com's Answer #565619 by Theo(13342)\"\" \"About 
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the formula is:\r
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\n" ); document.write( "\n" ); document.write( "An = A1 * n^3\r
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\n" ); document.write( "\n" ); document.write( "A1 = 1/3 * 1^3 = 1/3 * 1 = 1/3
\n" ); document.write( "A2 = 1/3 * 2^3 = 1/3 * 8 = 8/3
\n" ); document.write( "A3 = 1/3 * 3^3 = 1/3 * 27 = 27/3
\n" ); document.write( "A4 = 1/3 * 4^3 = 1/3 * 64 = 64/3
\n" ); document.write( "A5 = 1/3 * 5^3 = 1/3 * 125 = 125/3\r
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\n" ); document.write( "\n" ); document.write( "this is a geometric type sequence with a common ratio of n^3.\r
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\n" ); document.write( "\n" ); document.write( "this is not a pure geometric sequence because the ratio changes each time.\r
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\n" ); document.write( "\n" ); document.write( "in a pure geometric sequence the ratio remains the same.
\n" ); document.write( "an example of that would be An = 1/3 * 2^(n-1), where the common ratio is 2 and will always be 2.\r
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\n" ); document.write( "\n" ); document.write( "with this sequence, you get An = A1 * n^3 where the common ratio is n^3 that keeps changing as you go from one n to another. when n = 2, the common ratio is 2^3, when n = 3, the common ratio is 3^3, etc. the only common thing about it is that n is constantly being cubed.\r
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