document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=931553>Question 931553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A roofer and an assistant can repair a roof together in 7 hours. Working alone, the assistant can complete the repair in 16 hours. If both the roofer and the assistant work together for 4 hours and then the assistant is left alone to finish the job, how much longer should the assistant need to finish the repairs? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565611 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A roofer and an assistant can repair a roof together in 7 hours. Working alone, the assistant can complete the repair in 16 hours. If both the roofer and the assistant work together for 4 hours and then the assistant is left alone to finish the job, how much longer should the assistant need to finish the repairs?\r<BR>\n" );
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document.write( "A roofer and an assistant can repair a roof together in 7 hours. <BR>\n" );
document.write( "they together do 1/7 of the job in 1 hour\r<BR>\n" );
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document.write( "Working alone, the assistant can complete the repair in 16 hours.<BR>\n" );
document.write( "Assistant can do 1/16 of the job in 1 hour\r<BR>\n" );
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document.write( " If both the roofer and the assistant work together for 4 hours<BR>\n" );
document.write( "So they do 4/7 of the job\r<BR>\n" );
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document.write( "So 1-4/7 = 3/7 of the job left over\r<BR>\n" );
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document.write( "1 job, assistant does in 16 hours<BR>\n" );
document.write( "3/7 of the job he does in (3/7 * 16)\r<BR>\n" );
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document.write( "6.86 hours<BR>\n" );
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