document.write( "Question 931200: A rectangle has a length of 6 cm is greater than its width. Find its width given that it's area is 91 cm^2 \n" ); document.write( "
Algebra.Com's Answer #565518 by ptfile(81)\"\" \"About 
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Let x = The width
\n" ); document.write( " x+6 = The length\r
\n" ); document.write( "\n" ); document.write( "Formula for area of a rectangle
\n" ); document.write( "Area = Length x Width\r
\n" ); document.write( "\n" ); document.write( "It's area is 91 cm^2.\r
\n" ); document.write( "\n" ); document.write( " (x+6)(x)=91
\n" ); document.write( " x^2+6x=91
\n" ); document.write( " x^2+6x-91=0
\n" ); document.write( "(x+13)(x-7)=0\r
\n" ); document.write( "\n" ); document.write( "x=-13 or
\n" ); document.write( "x= 7\r
\n" ); document.write( "\n" ); document.write( "Substitute x for -13
\n" ); document.write( "(-13+6)(-13)=91
\n" ); document.write( " (-7)(-13)=91
\n" ); document.write( " 91=91 \r
\n" ); document.write( "\n" ); document.write( "Substitute x for 7
\n" ); document.write( " (7+6)(7) =91
\n" ); document.write( " (13)(7) =91
\n" ); document.write( " 91 =91\r
\n" ); document.write( "\n" ); document.write( "The width can either be -13cm or 7cm. Since the are no negative integers on finding the length, the width should be 7cm.\r
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