document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636600>Question 636600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 111. The third number is 3 times the first. The first number is 6 less than the second. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565517 by </B><A HREF=/tutors/aboutme.mpl?userid=ptfile><B>ptfile(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptfile><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptfile><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the second number<BR>\n" );
document.write( "  x-6 = the first number<BR>\n" );
document.write( "3(x-6)= the third number\r<BR>\n" );
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document.write( "The sum of three numbers is 111.<BR>\n" );
document.write( "x-6+x+3(x-6)=111<BR>\n" );
document.write( " x-6+x+3x-18=111 <BR>\n" );
document.write( "       5x-24=111<BR>\n" );
document.write( "          5x=135<BR>\n" );
document.write( "           x=27\r<BR>\n" );
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document.write( "Substitute x for 27<BR>\n" );
document.write( "27-6=21<BR>\n" );
document.write( "3(27-6)=63\r<BR>\n" );
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document.write( "The numbers are 21,27 and 63. </SPAN>\n" );
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