document.write( "Question 78680: Please solve. |x - 1.5| <= 3\r
\n" ); document.write( "\n" ); document.write( "I tried and got X <= 4.5 or X >= -1.5
\n" ); document.write( "

Algebra.Com's Answer #56550 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Your answers are correct. Good job!
\n" ); document.write( ".
\n" ); document.write( "In the way of discussion you can solve problems like this by using the plus and minus
\n" ); document.write( "quantities inside the absolute value signs. Work them like equations, except for one
\n" ); document.write( "exception ... if you multiply or divide both sides by a negative quantity, you reverse
\n" ); document.write( "the direction of the inequality sign.
\n" ); document.write( ".
\n" ); document.write( "Let's apply these techniques to this problem.
\n" ); document.write( ".
\n" ); document.write( "First, the quantity inside the absolute value signs is (x - 1.5).
\n" ); document.write( ".
\n" ); document.write( "Next put a plus sign in front of this quantity and you get the inequality:
\n" ); document.write( ".
\n" ); document.write( "+(x - 1.5) <= 3
\n" ); document.write( ".
\n" ); document.write( "Apply the procedures just as you would a equation. Begin by adding 1.5 to both sides
\n" ); document.write( "to remove the 1.5 from the left side. This makes the equation become:
\n" ); document.write( ".
\n" ); document.write( "x <= 3 + 1.5
\n" ); document.write( ".
\n" ); document.write( "add the terms on the right side and you get:
\n" ); document.write( ".
\n" ); document.write( "x <= 4.5 ... the same answer that you got.
\n" ); document.write( ".
\n" ); document.write( "Now for the second case. Use the quantity inside the absolute value signs, only precede
\n" ); document.write( "it by a negative sign. This makes the inequality:
\n" ); document.write( ".
\n" ); document.write( "-(x - 1.5) <= 3
\n" ); document.write( ".
\n" ); document.write( "The negative sign in front of the parentheses means that you are multiplying the quantity
\n" ); document.write( "in parentheses by -1. This results in:
\n" ); document.write( ".
\n" ); document.write( "-x + 1.5 <= 3
\n" ); document.write( ".
\n" ); document.write( "Get rid of the 1.5 on the left side by subtracting 1.5 from both sides. This simplifies
\n" ); document.write( "the equation to:
\n" ); document.write( ".
\n" ); document.write( "-x <= 3 - 1.5
\n" ); document.write( ".
\n" ); document.write( "On the right side of the inequality the two terms combine to 1.5 This makes the inequality
\n" ); document.write( "become:
\n" ); document.write( ".
\n" ); document.write( "-x <= 1.5
\n" ); document.write( ".
\n" ); document.write( "But we need to solve for +x. So multiply both sides by -1. (Don't forget the rule that
\n" ); document.write( "if you multiply or divide both sides by a negative number, you need to reverse the
\n" ); document.write( "direction of the inequality sign.) When you do these to things (multiply by -1 and
\n" ); document.write( "reverse the direction) you get:
\n" ); document.write( ".
\n" ); document.write( "x >= -1.5
\n" ); document.write( ".
\n" ); document.write( "This also is the same as your answer.
\n" ); document.write( ".
\n" ); document.write( "You can write the two answers in a \"one-liner\". When you say that x must be greater
\n" ); document.write( "than or equal to -1.5 that means it must be at or to the right of 1.5 on the number
\n" ); document.write( "line. But you also know that x must be equal to or to the left of +4.5 on the number line.
\n" ); document.write( "This can be written as:
\n" ); document.write( ".
\n" ); document.write( "- 1.5 <= x <= +4.5
\n" ); document.write( ".
\n" ); document.write( "Just to help you convince yourself that this is correct, select a number between -1.5 and
\n" ); document.write( "+4.5 set x equal to that number. For example, 0 is between those two limits. Setting
\n" ); document.write( "x equal to zero makes the original inequality:
\n" ); document.write( ".
\n" ); document.write( "\"abs%280+-+1.5%29+%3C=+3\"
\n" ); document.write( ".
\n" ); document.write( "This reduces to:
\n" ); document.write( ".
\n" ); document.write( "\"abs%28-1.5%29+%3C=+3\"
\n" ); document.write( ".
\n" ); document.write( "But the absolute value of -1.5 is +1.5 and so the inequality is:
\n" ); document.write( ".
\n" ); document.write( "\"1.5+%3C=+3\"
\n" ); document.write( ".
\n" ); document.write( "This is true, so that gives some confidence that we have the right answer. You can do
\n" ); document.write( "the same sort of analysis by picking a value for x that is less than -1.5 (say for example,
\n" ); document.write( "that x = -5). Substitute that value for x in the original problem and ensure yourself
\n" ); document.write( "that it does NOT satisfy the inequality. Do the same sort of analysis by letting x
\n" ); document.write( "be a value greater than +4.5 such as x = +5. Substitute +5 for x in the original
\n" ); document.write( "inequality and you should see that you get a value on the left side that is greater
\n" ); document.write( "than 3 ... meaning that the inequality does not work for values of x greater than 4.5.
\n" ); document.write( ".
\n" ); document.write( "Hope this discussion gives you a logical way to work problems of this type and how to
\n" ); document.write( "check to build confidence that your answer is correct.
\n" ); document.write( ".
\n" ); document.write( "Don't let the above discussion confuse you. You seem to know how to work problems
\n" ); document.write( "of this type. Keep up the good work.
\n" ); document.write( "
\n" );