document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=931182>Question 931182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help,<BR>\n" );
document.write( " A rectangle with diagnols 20cm has sides in the ratio 2:1. Find the: a) Perimeter b) Area\r<BR>\n" );
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document.write( "Thank you :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565490 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be a side then the sides are x, 2x and we have<BR>\n" );
document.write( "x^2 + (2x)^2 = 20^2<BR>\n" );
document.write( "x^2 + 4x^2 = 400<BR>\n" );
document.write( "5x^2 = 400<BR>\n" );
document.write( "x^2 = 80<BR>\n" );
document.write( "x = square root (80) = 8.94427191 cm<BR>\n" );
document.write( "2x = 17.88854382 cm<BR>\n" );
document.write( "Perimeter = 2x + 4x = 6x = 6*8.94427191 = 53.66563146 cm<BR>\n" );
document.write( "Area = x * 2x = 2x^2 = 2*(8.94427191)^2 = 160 cm^2 </SPAN>\n" );
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