document.write( "Question 931147: answer this please. a number is increased by two the square root of this result is less than the square root of half the number is 3. find the number. \n" ); document.write( "
Algebra.Com's Answer #565465 by ptfile(81) You can put this solution on YOUR website! Let x = The Number\r \n" ); document.write( "\n" ); document.write( "A number is increased by two the square root of this result is less than the square root of half the number is 3. \n" ); document.write( " √(x+2)-√(x/2)=3 \n" ); document.write( " √(x+2)=√(x/2)+3 \n" ); document.write( " (√(x+2))^2=((√(x/2)+3)^2 \n" ); document.write( " x+2=x/2+6√(x/2)+9 \n" ); document.write( " 0 =-x-2+x/2+6√(x/2)+9 \n" ); document.write( " 0 =-x/2+6√(x/2)+7 \n" ); document.write( " 0 =-x/2+(6√(x/2))(√(2/2))+7 \n" ); document.write( " 0 =-x/2+6√2x/2+7 \n" ); document.write( " 0 =-x/2+6√2x/2+14/2 \n" ); document.write( " 0 =-x+6√2x+14 \n" ); document.write( " x-14 = 6√2x \n" ); document.write( " (x-14)^2= (6√2x)^2 \n" ); document.write( " x^2-28x+196= 72x \n" ); document.write( "x^2-28x+196-72x=0 \n" ); document.write( " x^2-100x+196=0 \n" ); document.write( "Use Quadratic formula to solve for x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=98 \n" ); document.write( "or \n" ); document.write( "x=2\r \n" ); document.write( "\n" ); document.write( "Substitute x for 98 \n" ); document.write( " √(98+2)-√(98/2)=3 \n" ); document.write( " √100-√49=3 \n" ); document.write( " 10-7=3 \n" ); document.write( " 3=3\r \n" ); document.write( "\n" ); document.write( "Substitute x for 2 \n" ); document.write( "√(2+2)-√(2/2)=3 \n" ); document.write( " √(4)-√(1)=3 \n" ); document.write( " 2-1=3 \n" ); document.write( " 1=3\r \n" ); document.write( "\n" ); document.write( "The number is 98. \n" ); document.write( " |