document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=931137>Question 931137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three feet less than twice its width. If the perimeter is 24 feet, what is the length of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565463 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w and L;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=-3%2B2w ALIGN=MIDDLE  ALT=\"L=-3%2B2w\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2w%2B2L=24 ALIGN=MIDDLE  ALT=\"2w%2B2L=24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The perimeter equation can be simplified, and a substitution for L can be made. </SPAN>\n" );
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