document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=931101>Question 931101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled 60 mi at a constant rate before reducing the speed by 5 mph. Another 40 mi was traveled at the reduced speed. The total time for the 100-mile trip was 8 h. Find the rate during the first 60 mi. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565457 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 60 miles at speed x mph\r<BR>\n" );
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document.write( "40 miles at (x-5) mph\r<BR>\n" );
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document.write( "Total time = 8 hours\r<BR>\n" );
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document.write( "time first leg + time second leg = 8\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "60/x + 40/(x-5) = 8\r<BR>\n" );
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document.write( "multiply equation by x(x-5)\r<BR>\n" );
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document.write( "60(x-5)+40x = 8x(x-5)\r<BR>\n" );
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document.write( "60x-300+60=8x^2-40x\r<BR>\n" );
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document.write( "8x^2-140x+300=0\r<BR>\n" );
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document.write( "/4<BR>\n" );
document.write( "2x^2-35x+75=0\r<BR>\n" );
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document.write( "2x^2-30x-5x+75=0\r<BR>\n" );
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document.write( "2x(x-15)-5(x-15)=0\r<BR>\n" );
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document.write( "(x-15)(2x-5)=0\r<BR>\n" );
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document.write( "x= 15 OR x=5/2\r<BR>\n" );
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document.write( "5/2 is not possible\r<BR>\n" );
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document.write( "so speed = 15 mph </SPAN>\n" );
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