document.write( "Question 931108: how to factor (5n^2 +3)(n-2) \n" ); document.write( "
Algebra.Com's Answer #565430 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "how to factor \r
\n" ); document.write( "\n" ); document.write( "\"%285n%5E2+%2B3%29%28n-2%29\" ....this is factored already; multiply to see where we got it from\r
\n" ); document.write( "\n" ); document.write( "\"5n%5E3-10n%5E2%2B3n-6+\"...if we group terms\r
\n" ); document.write( "\n" ); document.write( "\"%285n%5E3-10n%5E2%29%2B%283n-6%29+\" and factor out \"5n%5E2\" from first group and \"3\" from second group, we get\r
\n" ); document.write( "\n" ); document.write( "\"5n%5E2%28n-2%29%2B3%28n-2%29+\" and\r
\n" ); document.write( "\n" ); document.write( "\"%285n%5E2%2B3%29%28n-2%29+\" we got same as at very beginning
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