document.write( "Question 10730: I can't solve this one inequality. Can someone please explain it to me and help????????? My teacher works at a high pace and I can never understand anything she does.\r
\n" ); document.write( "\n" ); document.write( "9x-99 is more than or equal to 18x. ????????? : (\r
\n" ); document.write( "\n" ); document.write( "Thankyou.
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Algebra.Com's Answer #5654 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
\"9x-99+%3E=+18x\" Subtract 9x from both sides.\r
\n" ); document.write( "\n" ); document.write( "\"-99+%3E=+9x\" Divide both sides by 9.\r
\n" ); document.write( "\n" ); document.write( "\"-11+%3E=+x\" or \"x+%3C=+-11\"
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