document.write( "Question 930177: A number increased by its square is equal to 9 times the next number. Find the number \n" ); document.write( "
Algebra.Com's Answer #565343 by ptfile(81)![]() ![]() You can put this solution on YOUR website! Let x = smaller number \n" ); document.write( " x+1= larger number\r \n" ); document.write( "\n" ); document.write( "A number increased by its square is equal to 9 times the next number \n" ); document.write( "x^2 = 9(x+1) \n" ); document.write( "x^2 = 9x+9\r \n" ); document.write( "\n" ); document.write( "x^2-9x-9 = 0\r \n" ); document.write( "\n" ); document.write( "Use Quadratic formula to solve for x \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=9.9083269131959839396788319012057 or 10 \n" ); document.write( "or \n" ); document.write( "x=-0.908326913195983939678831901205 or -1\r \n" ); document.write( "\n" ); document.write( "Substitute x with 10 \n" ); document.write( "(10)^2 = 9(10+1) \n" ); document.write( " 100 = 9(11) \n" ); document.write( " 100 = 99 \n" ); document.write( "Substitute x with -1 \n" ); document.write( "(-1)^2 = 9(-1+1) \n" ); document.write( " 1 = 9(0) \n" ); document.write( " 1 = 0\r \n" ); document.write( "\n" ); document.write( "The number is -1 or 10.\r \n" ); document.write( "\n" ); document.write( "You could also use completing the square to solve for x \n" ); document.write( "x^2-9x-9= 0 \n" ); document.write( "Add 9 on both side \n" ); document.write( "x^2-9x+9= 0+9 \n" ); document.write( "x^2-9x = 9 \n" ); document.write( "Divide B coefficient by 2 and square it. Then add it on both side \n" ); document.write( "x^2-9x+81/4=9+81/4 \n" ); document.write( "x^2-9x+81/4=36/4+81/4 \n" ); document.write( "x^2-9x+81/4=117/4 \n" ); document.write( " (x-9/2)^2=117/4 \n" ); document.write( "Square root on both side \n" ); document.write( "√(x-9/2)^2 = √117/4 \n" ); document.write( "x-9/2 = 3/2√13 \n" ); document.write( "Add 9/2 on both side. Add ± on the right side. \n" ); document.write( "x-9/2+9/2 =9/2±3/2√13 \n" ); document.write( "x = 9/2 ±3/2√13 \n" ); document.write( " \n" ); document.write( "x = 9.9083269131959839396788319012057 or 10 \n" ); document.write( "or \n" ); document.write( "x = -0.908326913195983939678831901205 or -1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |