document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930832>Question 930832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Uniform motion problem.....please help me solve this too..................... *An airplane leaves Davao International airport bound for Manila at 9:50 am,cruising at 480 kph.A second airplane leaves Davao for the same destination at 10:05 am,cruising 600 kph.How long will it take and in what time the second airplane to arrive in Manila with the same arrival of the first airplane?(the same arrival means they traveled the same distance) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565308 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a1 leaves Davao at  9:50am for Manila cruising at 480 kph<BR>\n" );
document.write( "a2 leaves Davao at 10:05am for Manila cruising at 600 kph<BR>\n" );
document.write( "let x be the time it takes a2 to travel to Manila<BR>\n" );
document.write( "a1 has a head start of 15 minutes or .25 hour<BR>\n" );
document.write( "we have the following two equations set equal to each other, we use rate * time = distance<BR>\n" );
document.write( "480*(x + .25) = 600 * x<BR>\n" );
document.write( "480x + 120 = 600x<BR>\n" );
document.write( "120x = 120<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "a2 arrives at 11:05am and takes 1 hour<BR>\n" );
document.write( " </SPAN>\n" );
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