document.write( "Question 930777: A canoe goes 12 miles downstream in the same time it takes to go 8 miles upstream. If the canoe can go 15 mph in still water, what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #565297 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed = 15 mph \n" ); document.write( "current speed = x mph \n" ); document.write( " \n" ); document.write( "speed against current 15 - x \n" ); document.write( "speed with current 15 + x \n" ); document.write( " \n" ); document.write( "Distance against current 8 miles \n" ); document.write( "Distance with current 12 miles \n" ); document.write( " \n" ); document.write( "t=d/r time against = time with current - \n" ); document.write( "8 / ( 15 - x )= 12 / ( 15 + x ) \n" ); document.write( "8 ( 15 + x )= 12 ( 15 -x ) \n" ); document.write( "120 + 8 x = 180 - -12 x \n" ); document.write( "12 x 8 x 180 + -120 \n" ); document.write( "20 x = 60 \n" ); document.write( "/ 20 \n" ); document.write( "x = 3 mph current speed \n" ); document.write( " \n" ); document.write( " |