document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930798>Question 930798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if measure of angle A=60 degrees and side AB=5, then side BC=? It is a right triangle with the 90 degree angle at the top point of the triangle.  So the triangle has A on right point of triangle, B on top point of triangle(where 90 degree angle is) and C on left point of triangle.  I tried to solve by using tan, but the answer is not correct.  The answer sheet says the answer is 5 sq rt 3.  We haven't been taught how to do sine or cosine yet so I don't believe that will help me.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565296 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If B = 90<BR>\n" );
document.write( "& A= 60<BR>\n" );
document.write( "Then c=30 (A+C)=90\r<BR>\n" );
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document.write( "AB = 5\r<BR>\n" );
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document.write( "AB/BC= tan 30\r<BR>\n" );
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document.write( "AB/tan 30 = BC\r<BR>\n" );
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document.write( "5/(1/sqrt(3))=BC\r<BR>\n" );
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document.write( "BC = 5 sqrt(3)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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