document.write( "Question 930749: Hi would you please help me with my homework.\r
\n" ); document.write( "\n" ); document.write( "Suppose that an automobile loses 1/5 of its value each year; that is at the end of a given year the value is 4/5 of the value at the beginning of that year. If a car costs $24,000 new, What is the value at the end of five years?\r
\n" ); document.write( "\n" ); document.write( "My professor said that the answer is $7864. \r
\n" ); document.write( "\n" ); document.write( "Would you please show me the steps on how to solve this problem. Thank you.
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Algebra.Com's Answer #565256 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This works just like your other question. v for value after any given t number of years, \"v=24000%284%2F5%29%5Et\". What is v when t=5? You could if you wish, compute for each the the five successive years, year by year.\r
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\n" ); document.write( "\n" ); document.write( "The sophisticated way is to either use a calculator or table of logarithms and algebra.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"v=24000%284%2F5%29%5E5\"
\n" ); document.write( "\"v=7864\"\r
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\n" ); document.write( "\n" ); document.write( "The long way:
\n" ); document.write( "Year_________________Value
\n" ); document.write( "0_____________________24000
\n" ); document.write( "1_____________________19200
\n" ); document.write( "2_____________________15360
\n" ); document.write( "3_____________________12288
\n" ); document.write( "4______________________9830
\n" ); document.write( "5______________________7863
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