document.write( "Question 930524: If a = 10 b= 20 and angle of C= 30 degrees solve for the missing pieces of the triangle:\r
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Algebra.Com's Answer #565216 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! If a = 10 b= 20 and angle of C= 30 degrees solve for the missing pieces of the triangle: \n" ); document.write( "angle A= \n" ); document.write( "angle B= \n" ); document.write( "c= \n" ); document.write( "*** \n" ); document.write( "law of cosine: c^2=a^2+b^2-2abcosC,a and b are the two sides with the included angle C, c=side opposite angle C. \n" ); document.write( "law of sine: SinC/c=sinA/a, c and a are sides opposite angles C and A \n" ); document.write( ".. \n" ); document.write( "c^2=10^2+20^2-2*10*20*cos30˚ \n" ); document.write( "c^2=100+400-400(√3/2) \n" ); document.write( "c^2=500-346.41=153.60 \n" ); document.write( "c=12.4 \n" ); document.write( ".. \n" ); document.write( "sinC/c=sinB/b \n" ); document.write( "12.4sinB=20sinC \n" ); document.write( "sinB=20(1/2)/12.4 \n" ); document.write( "sinB=.8065 \n" ); document.write( "B=53.76˚ \n" ); document.write( ".. \n" ); document.write( "sinC/c=sinA/a \n" ); document.write( "12.4sinA=10sinC \n" ); document.write( "sinA=10(1/2)/12.4 \n" ); document.write( "sinA=.4032 \n" ); document.write( "A=23.78˚\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |