document.write( "Question 930667: Suppose a car driven under different conditions gets a mean gas mileage of 40 miles per gallon with a standard deviation of 3 miles per gallon. If you drive this car many times, your mileage on 99.7% of the trips will be between \n" ); document.write( "
Algebra.Com's Answer #565215 by stanbon(75887)\"\" \"About 
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Suppose a car driven under different conditions gets a mean gas mileage of 40 miles per gallon with a standard deviation of 3 miles per gallon. If you drive this car many times, your mileage on 99.7% of the trips will be between
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\n" ); document.write( "x-bar = 40 mpg
\n" ); document.write( "ME = z*s/sqrt(n) = 2.967*3/sqrt(n)
\n" ); document.write( "Note:: \"n\" was not specified in your post.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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