document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930669>Question 930669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	The mean SAT verbal score is 412, with a standard deviation of 90. Use the Empirical Rule to determine what percent of the scores lie between 412 and 592. (Assume the data set has a bell-shaped distribution.)<BR>\n" );
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document.write( "	a-34%<BR>\n" );
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document.write( "	b-81.5%<BR>\n" );
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document.write( "	c-47.5%<BR>\n" );
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document.write( "	d-68%<BR>\n" );
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document.write( "	e-None of the above<BR>\n" );
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document.write( "        f-49.9%\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565212 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50%  to the right<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C200%2C-5%2C5%2C-.5%2C1.5%2C+graph%28400%2C200%2C-5%2C5%2C-.5%2C1.5%2C+exp%28-x%5E2%2F2%29%29%2C+green%28line%281%2C0%2C1%2Cexp%28-1%5E2%2F2%29%29%2Cline%28-1%2C0%2C-1%2Cexp%28-1%5E2%2F2%29%29%29%2Cgreen%28line%282%2C0%2C2%2Cexp%28-2%5E2%2F2%29%29%2Cline%28-2%2C0%2C-2%2Cexp%28-2%5E2%2F2%29%29%29%2Cgreen%28line%283%2C0%2C3%2Cexp%28-3%5E2%2F2%29%29%2Cline%28-3%2C0%2C-3%2Cexp%28-3%5E2%2F2%29%29%29%2Cgreen%28line%28+0%2C0%2C+0%2Cexp%280%5E2%2F2%29%29%29%2Clocate%284.8%2C-.01%2Cz%29%2Clocate%284.8%2C.2%2Cz%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "one  standard deviation from the mean accounts for about 68% of the set <BR>\n" );
document.write( "two standard deviations from the mean account for about 95%<BR>\n" );
document.write( "and three standard deviations from the mean account for about 99.7%.<BR>\n" );
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document.write( "mean =  412, with a standard deviation of 90.<BR>\n" );
document.write( "P(412 < x < 592) = (.95/2)  = .475  0r 47.5% </SPAN>\n" );
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