document.write( "Question 78773: Can someone help me with these, please?\r
\n" ); document.write( "\n" ); document.write( "1) squrt y+7=2\r
\n" ); document.write( "\n" ); document.write( "2) squrt 5x+5-5=0\r
\n" ); document.write( "\n" ); document.write( "Thanks!!!! :)
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Algebra.Com's Answer #56512 by sprolden(40)\"\" \"About 
You can put this solution on YOUR website!
1) squrt y+7=2\r
\n" ); document.write( "\n" ); document.write( "1- Square each side of the equation. (sqrt y+7)^2 = (2)^2
\n" ); document.write( "2- You should get y+7 = 4
\n" ); document.write( "3- Subtract 7 from both sides y+7-7 = 4-7
\n" ); document.write( "4- You should get y = -3\r
\n" ); document.write( "\n" ); document.write( "2) squrt 5x+5-5=0
\n" ); document.write( "1- First of all, 5-5 is 0, so you're left with sqrt 5x = 0
\n" ); document.write( "2- Square both sides (sqrt 5x)^2 = (0)^2
\n" ); document.write( "3- You should get 5x = 0
\n" ); document.write( "4- Divide both sides by 5 5/5 x = 0/5
\n" ); document.write( "5- You should get x = 0
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