document.write( "Question 78773: Can someone help me with these, please?\r
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document.write( "1) squrt y+7=2\r
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document.write( "2) squrt 5x+5-5=0\r
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document.write( "Thanks!!!! :) \n" );
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Algebra.Com's Answer #56512 by sprolden(40)![]() ![]() ![]() You can put this solution on YOUR website! 1) squrt y+7=2\r \n" ); document.write( "\n" ); document.write( "1- Square each side of the equation. (sqrt y+7)^2 = (2)^2 \n" ); document.write( "2- You should get y+7 = 4 \n" ); document.write( "3- Subtract 7 from both sides y+7-7 = 4-7 \n" ); document.write( "4- You should get y = -3\r \n" ); document.write( "\n" ); document.write( "2) squrt 5x+5-5=0 \n" ); document.write( "1- First of all, 5-5 is 0, so you're left with sqrt 5x = 0 \n" ); document.write( "2- Square both sides (sqrt 5x)^2 = (0)^2 \n" ); document.write( "3- You should get 5x = 0 \n" ); document.write( "4- Divide both sides by 5 5/5 x = 0/5 \n" ); document.write( "5- You should get x = 0 \n" ); document.write( " |