document.write( "Question 930521: how do i find the inverse of f(x)=x^3+8 \n" ); document.write( "
Algebra.Com's Answer #565066 by MathLover1(20850)\"\" \"About 
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find the inverse of \"f%28x%29=x%5E3%2B8\":\r
\n" ); document.write( "\n" ); document.write( "first, recall that \"f%28x%29=y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=x%5E3%2B8\" ...now, swap \"x\" and \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=y%5E3%2B8\" ...solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x-8=y%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"root%283%2C%28x-8%29%29=y\"\r
\n" ); document.write( "\n" ); document.write( "so, inverse is\r
\n" ); document.write( "\n" ); document.write( "\"f%5E-1%28x%29=root%283%2C%28x-8%29%29\" or \"f%5E-1%28x%29=%28x-8%29%5E%281%2F3%29\"\r
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