document.write( "Question 930458: How do I solve this system using elimination? In steps please.\r
\n" ); document.write( "\n" ); document.write( "6/x-3/y=-4 and 9/x+9/y=21
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Algebra.Com's Answer #565065 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "How do I solve this system using elimination? In steps please.\r
\n" ); document.write( "\n" ); document.write( "6/x-3/y=-4 and 9/x+9/y=21
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Let \"x+=+1%2Fa\", and \"y+=+1%2Fb\"
\n" ); document.write( "Then:
\n" ); document.write( "\"6%2Fx+-+3%2Fy+=+-+4\" becomes: 6a – 3b = - 4 ------- eq (i)
\n" ); document.write( "\"9%2Fx+%2B+9%2Fy+=+21\" becomes: 9a + 9b = 21_____3(3a + 3b) = 3(7)_____3a + 3b = 7 ---------- eq (ii)
\n" ); document.write( "9a = 3 --------- Adding eqs (ii) &(i)
\n" ); document.write( "\"a+=+3%2F9\", or \"1%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"6%281%2F3%29+-+3b+=+-+4\" --------- Substituting 1/3 for a in eq (i)
\n" ); document.write( "2 – 3b = – 4
\n" ); document.write( "– 3b = – 4 – 2
\n" ); document.write( "– 3b = – 6
\n" ); document.write( "\"b+=+%28-+6%29%2F%28-+3%29\", or \"2\"\r
\n" ); document.write( "\n" ); document.write( "Since \"a+=+1%2F3\", then \"1%2Fa+=+1%2F%281%2F3%29\", or \"3\"
\n" ); document.write( "Now, since \"x+=+1%2Fa+=+3\", then \"highlight_green%28x+=+3%29\"\r
\n" ); document.write( "\n" ); document.write( "Since b = 2, then \"1%2Fb+=+1%2F2\"
\n" ); document.write( "Now, since \"y+=+1%2Fb+=+1%2F2\", then \"highlight_green%28y+=+1%2F2%29\"
\n" ); document.write( "You can do the check!!
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