document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930449>Question 930449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Don randomly draws two cards from a standard deck of 52 cards. He does not replace the first card. What is the probability that both cards are aces? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565050 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(1st card is ace) = 4/52 = 1/13\r<BR>\n" );
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document.write( "P(2nd card is ace) = 3/51\r<BR>\n" );
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document.write( "P(both cards are aces) = P(1st card is ace)*P(2nd card is ace) \r<BR>\n" );
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document.write( "P(both cards are aces) = (1/13)*(3/51)\r<BR>\n" );
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document.write( "P(both cards are aces) = 3/663\r<BR>\n" );
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document.write( "P(both cards are aces) = 1/221\r<BR>\n" );
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