document.write( "Question 930461: Three adults and four children must pay $95. Two adults and three children must pay $67. Find the price of the tickets for adult and child \n" ); document.write( "
Algebra.Com's Answer #565033 by algebrahouse.com(1659)\"\" \"About 
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a = price of adult
\n" ); document.write( "c = price of child\r
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\n" ); document.write( "\n" ); document.write( "3a + 4c = 95 {three adults and 4 children is $95}
\n" ); document.write( "2a + 3c = 67 {two adults and 3 children is $67}\r
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\n" ); document.write( "\n" ); document.write( "-6a - 8c = -190 {multiplied top equation by -2}
\n" ); document.write( "6a + 9c = 201 {multiplied bottom equation by 3}
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\n" ); document.write( "c = 11 {added the two equations together}\r
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\n" ); document.write( "\n" ); document.write( "3a + 4c = 95 {top equation}
\n" ); document.write( "3a + 4(11) = 95 {substituted 11, in for c, into top equation}
\n" ); document.write( "3a + 44 = 95 {multiplied 4 by 11}
\n" ); document.write( "3a = 51 {subtracted 44 from each side}
\n" ); document.write( "a = 17 {divided each side by 3}\r
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\n" ); document.write( "\n" ); document.write( "adult ticket is $17
\n" ); document.write( "child ticket is $11
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\n" ); document.write( "Also, the graph of the two equations shows the point of intersection as (17,11)
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