document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1671>Question 1671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have no clue how to do this.  I am working on quadratic functions and their graphs in intermediate algebra.  This is one question with three parts:\r<BR>\n" );
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document.write( "A. Write the function y=3(x-2)^2+6 in the form of Y=ax^2 +bx+c, and find the  <BR>\n" );
document.write( "   vertex of the parabola using the formula x=-b/2a<BR>\n" );
document.write( "B. Repeat part (a) with the functions y=-4((x-5)^2-9 and y=3(x+2)^2-6.<BR>\n" );
document.write( "C. What is the vertex for a parabola that is written in the form y=a(x-h)^2+k? <BR>\n" );
document.write( "   Explain your answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565 by </B><A HREF=/tutors/aboutme.mpl?userid=smartdude17><B>smartdude17(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=smartdude17><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> WOW, I've already finished this topic and I'm in seventh grade(lol). Well to find the vertex of a parabola, you use -b/2a. Your equation is this and I'll try to help you solve it from the way you have written it.<BR>\n" );
document.write( "y=3(x-2)^2+6<BR>\n" );
document.write( "Now you would clear the parenthesis by:<BR>\n" );
document.write( "y=3(x^2-4)+6 this turns into this:<BR>\n" );
document.write( "y=3x^2-12+6<BR>\n" );
document.write( "Now you need to simplify it:<BR>\n" );
document.write( "y=3x^2-6<BR>\n" );
document.write( "Now you can do the QF (quadratic formula)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%280%2B-sqrt%280%2B72%29%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x=%280%2B-sqrt%280%2B72%29%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Substitution<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28%2B-4sqrt%2818%29%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x=%28%2B-4sqrt%2818%29%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And this is your scantron answer. Or you could do method #2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%280%2B-8+8%2F17%29%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x=%280%2B-8+8%2F17%29%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So this is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28%2B-8+8%2F17%29%29%2F%286%29 ALIGN=MIDDLE  ALT=\"x=%28%2B-8+8%2F17%29%29%2F%286%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And now you M.A.D. it by multiplying 17 and 8 then adding 8 which equals 144/17 and then you multiply it with 1/6 which equals 24/17 and -24/17 </SPAN>\n" );
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