document.write( "Question 930421: I need help with this particular question.
\n" ); document.write( "sec H= 25/24 and angle H is in QIV. Find tan 2H. I started off with the equation tan 2H= 2(tanH)/1-tan^2H) I plugged in the values, but I keep getting the wrong answer. Can anyone help me. Thanks in advance.
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Algebra.Com's Answer #564991 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
sec H= 25/24
\n" ); document.write( "cos H = 24/25 \"sqrt%2825%5E2+-+24%5E2%29+=+sqrt%2849%29\" = 7
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\n" ); document.write( "Q IV
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\n" ); document.write( "sin H = -7/25
\n" ); document.write( "tan H = sin/cos = -7/24
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\n" ); document.write( "tan 2H = (2tan H)/(1 - tan^2 H) =
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