document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930418>Question 930418</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Approximate the following logarithm using the properties of logarithms given.<BR>\n" );
document.write( "logb(2)=0.216<BR>\n" );
document.write( "logb(3)=0.343<BR>\n" );
document.write( "logb(5)=0.502\r<BR>\n" );
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document.write( "logb(25b^2)=???\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564986 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(25b^2) = log(25) + 2log(b)<BR>\n" );
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document.write( "----<BR>\n" );
document.write( "log(25b^2) = log(5^2) + 2<BR>\n" );
document.write( "= 2log(5) + 2<BR>\n" );
document.write( "= 1.004 + 2<BR>\n" );
document.write( "= 3.004 </SPAN>\n" );
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