document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930389>Question 930389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let theta be an angle in quad III such that sec theta = -13/5. Find the exact values of cot theta and sin theta?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564932 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let theta be an angle in quad III such that sec theta = -13/5. Find the exact values of cot theta and sin theta?<BR>\n" );
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document.write( "Note:: both x and y are negative in QIII<BR>\n" );
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document.write( "By definition, sec = r/x<BR>\n" );
document.write( "Since sec(t) = -13/5, r = 13 and x = -5<BR>\n" );
document.write( "Then y = -sqrt[13^2-5^2] = -sqrt(144) = -12<BR>\n" );
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document.write( "Ans:<BR>\n" );
document.write( "cot(t) = x/y = -5/-12 = 5/12<BR>\n" );
document.write( "sin(t) = y/r = -12/13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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