document.write( "Question 930348: solve using the substitution method\r
\n" ); document.write( "\n" ); document.write( "5x+3y=80
\n" ); document.write( "2x+y=30
\n" ); document.write( "

Algebra.Com's Answer #564919 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
From eq. 2,
\n" ); document.write( "\"y=-2x%2B30\"
\n" ); document.write( "Substitute into eq. 1,
\n" ); document.write( "\"5x%2B3%28-2x%2B30%29=80\"
\n" ); document.write( "\"5x-6x%2B90=80\"
\n" ); document.write( "\"-x=-10\"
\n" ); document.write( "\"x=10\"
\n" ); document.write( "Then,
\n" ); document.write( "\"y=-2%2810%29%2B30\"
\n" ); document.write( "\"y=-20%2B30\"
\n" ); document.write( "\"y=10\"
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