document.write( "Question 930367: solve algebraically 4x^2+y^2=4 -2x+y=2 \n" ); document.write( "

Algebra.Com's Answer #564917 by Fombitz(32388) $\"\"$ $\"About$

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From eq. 2,
\n" ); document.write( " $\"2x=y-2\"$
\n" ); document.write( " $\"%282x%29%5E2=%28y-2%29%5E2\"$
\n" ); document.write( " $\"4x%5E2=y%5E2-4y%2B4\"$
\n" ); document.write( "Substitute into eq. 1,
\n" ); document.write( " $\"y%5E2-4y%2B4%2By%5E2=4\"$
\n" ); document.write( " $\"2y%5E2-4y=0\"$
\n" ); document.write( " $\"y%5E2-2y=0\"$
\n" ); document.write( " $\"y%28y-2%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"y=0\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"2x=0-2%7D%7D%0D%0A%7B%7B%7Bx=-1\"$
\n" ); document.write( "and
\n" ); document.write( " $\"y-2=0\"$
\n" ); document.write( " $\"y=2\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"2x=2-2\"$
\n" ); document.write( " $\"2x=0\"$
\n" ); document.write( " $\"x=0\"$
\n" ); document.write( "So the solutions are (-1,0) and (0,2) \n" ); document.write( "

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