document.write( "Question 930333: a flat rectangular piece of iron has an area of 27 sq. ft. and perimeter of 21 ft. find the dimensions of the iron \n" ); document.write( "
Algebra.Com's Answer #564895 by sunny1992(35)![]() ![]() You can put this solution on YOUR website! convert the given into formula. \n" ); document.write( "rectangle's area formula = LxW \n" ); document.write( "rectangle's Perimeter formula = 2L+2W \n" ); document.write( "from the given values and formulas we can create 2 different eq ie \n" ); document.write( "LxW=27 \n" ); document.write( "2L+2W=21 \n" ); document.write( "solve eq 1 \n" ); document.write( "L=27/W \n" ); document.write( "put the value of L in eq 2 \n" ); document.write( "2(27/w)+2w=21 \n" ); document.write( "(54+2W^2)=21W \n" ); document.write( "2w^2-21W+54=0 \n" ); document.write( "use quadratic equation to solve it. \n" ); document.write( " |