document.write( "Question 930333: a flat rectangular piece of iron has an area of 27 sq. ft. and perimeter of 21 ft. find the dimensions of the iron \n" ); document.write( "
Algebra.Com's Answer #564895 by sunny1992(35)\"\" \"About 
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convert the given into formula.
\n" ); document.write( "rectangle's area formula = LxW
\n" ); document.write( "rectangle's Perimeter formula = 2L+2W
\n" ); document.write( "from the given values and formulas we can create 2 different eq ie
\n" ); document.write( "LxW=27
\n" ); document.write( "2L+2W=21
\n" ); document.write( "solve eq 1
\n" ); document.write( "L=27/W
\n" ); document.write( "put the value of L in eq 2
\n" ); document.write( "2(27/w)+2w=21
\n" ); document.write( "(54+2W^2)=21W
\n" ); document.write( "2w^2-21W+54=0
\n" ); document.write( "use quadratic equation to solve it.
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