document.write( "Question 930345: I am struggling with how to setup the problem and solve it.\r
\n" ); document.write( "\n" ); document.write( "If 10^3 = 0.477 how do I solve for\r
\n" ); document.write( "\n" ); document.write( "10^27
\n" ); document.write( "10^300
\n" ); document.write( "10^1/27
\n" ); document.write( "10^0.3\r
\n" ); document.write( "\n" ); document.write( "Guidance with how these numbers plug into an equation would be greatly appreciated \n" ); document.write( "
Algebra.Com's Answer #564892 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
Re TY:
\n" ); document.write( "First of all...what is mathematically true is that:
\n" ); document.write( "log 3 = .477
\n" ); document.write( "...this is an exercise in base 10 logarithms
\n" ); document.write( "3log 3 = 3(.477) = 1.431
\n" ); document.write( "Note: 3log 3 = log 3^3 = log (27)
\n" ); document.write( ".........
\n" ); document.write( "And ...
\n" ); document.write( "log(300) = log (3•100) = log 3 + log 100 = .477 + 2 = 2.477
\n" ); document.write( "log( 1/27) = log (3/81) = log 3 - log 81 = .477 - 1.908 = -1.431 (used calculator for log 81
\n" ); document.write( "log(.3) = log (3/10) = log 3 - log 10 = .477 - 1 = -.523
\n" ); document.write( "....
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