document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930224>Question 930224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr Edwards is now 3 times as old as his daughter.in 15 years time the sum of their age as will be 86<BR>\n" );
document.write( "   A)find their ages now<BR>\n" );
document.write( "   B)How old was Mr Edwards when his daughter was born  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564778 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = daughter's age now<BR>\n" );
document.write( "3x = Mr. Edwards' age now {he is 3 times his daughter}\r<BR>\n" );
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document.write( "x + 15 = daughter in 15 years {added 15 onto daughter's current age}<BR>\n" );
document.write( "3x + 15 = Mr. Edwards in 15 years {added 15 onto Mr. Edwards' current age}\r<BR>\n" );
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document.write( "x + 15 + 3x + 15 = 86 {sum of their ages, in 15 years, will be 86}<BR>\n" );
document.write( "4x + 30 = 86 {combined like terms}<BR>\n" );
document.write( "4x = 56 {subtracted 30 from each side}<BR>\n" );
document.write( "x = 14 {divided each side by 4}<BR>\n" );
document.write( "3x = 42 {substituted 14, in for x, into 3x}\r<BR>\n" );
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document.write( "His daughter is 14 and Mr. Edwards is 42, and<BR>\n" );
document.write( "Mr. Edwards was 28 when his daughter was born {subtracted 14 from 42}<BR>\n" );
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