document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930219>Question 930219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this:Solve the systems of non-linear equations.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+y%5E2 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=25<BR>\n" );
document.write( "                                            2x+4y=-10\r<BR>\n" );
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document.write( "(they are supposed to be stacked) I know how to do this equation without squares, I need help starting it with the squares.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564772 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x² + y² = 25<BR>\n" );
document.write( "2x + 4y = -10\r<BR>\n" );
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document.write( "2x + 4y = -10 {the second equation}<BR>\n" );
document.write( "2x = -4y - 10   {subtracted 4y from each side}<BR>\n" );
document.write( "x = -2y - 5   {divided each side by 2}\r<BR>\n" );
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document.write( "x² + y² = 25 {the first equation}<BR>\n" );
document.write( "(-2y - 5)² + y² = 25 {substituted (-2y - 5) , in for x, into top equation}<BR>\n" );
document.write( "(-2y - 5)(-2y - 5) + y² = 25 {when squaring a binomial, multiply it by itself}<BR>\n" );
document.write( "4y² + 20y + 25 + y² = 25 {used foil method}<BR>\n" );
document.write( "5y² + 20y + 25 = 25 {combined like terms}<BR>\n" );
document.write( "5y² + 20y = 0 {subtracted 25 from each side}<BR>\n" );
document.write( "5y(y + 4) = 0 {factored out the common factor, 5y}<BR>\n" );
document.write( "5y = 0 or y + 4 = 0 {set each factor equal to 0}<BR>\n" );
document.write( "y = 0 or y = -4 {solved each equation}\r<BR>\n" );
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document.write( "x = -2y - 5 {the re-arranged second equation}<BR>\n" );
document.write( "If y = 0:<BR>\n" );
document.write( "x = -2(0) - 5 {substituted 0 for y}<BR>\n" );
document.write( "x = 0 - 5 {multiplied}<BR>\n" );
document.write( "x = -5 {subtracted}<BR>\n" );
document.write( "(-5,0) is a solution {a point of intersection of the line and circle}\r<BR>\n" );
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document.write( "x = -2y - 5 {the re-arranged second equation}<BR>\n" );
document.write( "If y = -4:<BR>\n" );
document.write( "x = -2(-4) - 5 {substituted -4 for y}<BR>\n" );
document.write( "x = 8 - 5 {multiplied}<BR>\n" );
document.write( "x = 3 {subtracted}<BR>\n" );
document.write( "(3,-4) is a solution {a point of intersection of the line and circle}\r<BR>\n" );
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document.write( "x = -5 when y = 0 and x = 3 when y = -4<BR>\n" );
document.write( "(-5,0) and (3,-4) are points of intersection of the line and circle<BR>\n" );
document.write( "<br>For more help from me, visit: <a  rel=nofollow HREF= \"http://www.algebrahouse.com/\" target = \"_blank\">www.algebrahouse.com</a><br><br><br>\r<BR>\n" );
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