document.write( "Question 930211: Please help me solve this: $\"+find+f%5E-1++\"$ $\"+f%28x%29=%28x%2B2%29%5E2++\"$ x is greater than or equal to -2\r
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Algebra.Com's Answer #564767 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+f%28x%29=%28x%2B2%29%5E2++\"$ \r
\n" ); document.write( "\n" ); document.write( "to $\"+find+f%5E-1++\"$ first recall that $\"+f%28x%29=y++\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"y=%28x%2B2%29%5E2++\"$ ...swap $\"x\"$ and $\"y\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x=%28y%2B2%29%5E2++\"$ ...solve for $\"y\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"sqrt%28x%29=sqrt%28%28y%2B2%29%5E2%29++\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"sqrt%28x%29=y%2B2++\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"y=%28-2+%2B-+sqrt%28x+%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "so, $\"+find+f%5E-1+=%28-2+%2B-+sqrt%28x+%29%29+\"$ \r
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