document.write( "Question 930186: an airplane can travel 525 mph in still air. if it travels 3850 miles with the wind in the same amount of time as it can travel 3500 miles against the wind. What is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #564741 by TimothyLamb(4379)\"\" \"About 
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x = wind speed
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "t = d/s
\n" ); document.write( "---
\n" ); document.write( "with the wind:
\n" ); document.write( "t = 3850/(525 + x)
\n" ); document.write( "---
\n" ); document.write( "against the wind:
\n" ); document.write( "t = 3500/(525 - x)
\n" ); document.write( "---
\n" ); document.write( "equate the times:
\n" ); document.write( "3850/(525 + x) = 3500/(525 - x)
\n" ); document.write( "3850(525 - x) = 3500(525 + x)
\n" ); document.write( "3850*525 - 3850x = 3500*525 + 3500x
\n" ); document.write( "3500x + 3850x = 3850*525 - 3500*525
\n" ); document.write( "(3500 + 3850)x = 3850*525 - 3500*525
\n" ); document.write( "x = ( 3850*525 - 3500*525 ) / (3500 + 3850)
\n" ); document.write( "x = 25
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "x = wind speed = 25 mph
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