document.write( "Question 929930: Solve the problem. In one U.S. city, the quadratic function f(x)= 0.039x^2-0.48x+36.66 models the average age y, at which men were the first married x years after 1900. In which year was this average age at a minimum? (Round to the nearest year.) What was the average age that men were first married that year? (Round to the nearest tenth.) \n" ); document.write( "

Algebra.Com's Answer #564660 by TimothyLamb(4379) $\"\"$ $\"About$

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f(x)= 0.039x^2 - 0.48x + 36.66 = 0
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\n" ); document.write( "the above quadratic equation is in standard form, with a=0.039, b=-0.48 and c=36.66
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\n" ); document.write( "to solve the quadratic equation, by using the quadratic formula, copy and paste this:
\n" ); document.write( "0.039 -0.48 36.66
\n" ); document.write( "into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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\n" ); document.write( "the quadratic has a minimum at:
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\n" ); document.write( "( 6.15384615, 35.1830769 )
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\n" ); document.write( "answer:
\n" ); document.write( "the minimum occurred in the year 1900 + 6.15384615 = 1906
\n" ); document.write( "the average age that men were first married that year = 35.2
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