document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78646>Question 78646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by substitution.<BR>\n" );
document.write( "4x - 12y =5<BR>\n" );
document.write( "-x + 3y = -1\r<BR>\n" );
document.write( "\n" );
document.write( "Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56466 by </B><A HREF=/tutors/aboutme.mpl?userid=Septimus314><B>Septimus314(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Septimus314><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solving by substitution, you want to find what x or y equals from one of those equations, then plug what you find into the other equation, as follows:\r<BR>\n" );
document.write( "\n" );
document.write( "We can use the bottom line to find x:\r<BR>\n" );
document.write( "\n" );
document.write( "-x + 3y = -1<BR>\n" );
document.write( "get -x on one side\r<BR>\n" );
document.write( "\n" );
document.write( "-x = -3y - 1<BR>\n" );
document.write( "multiply all by -1\r<BR>\n" );
document.write( "\n" );
document.write( "x = 3y + 1\r<BR>\n" );
document.write( "\n" );
document.write( "Use this in the other equation.\r<BR>\n" );
document.write( "\n" );
document.write( "4(3y + 1) - 12y = 5<BR>\n" );
document.write( "12y + 4 - 12y = 5<BR>\n" );
document.write( "4 = 5\r<BR>\n" );
document.write( "\n" );
document.write( "Hmm...I am not finding this equation to be solvable.\r<BR>\n" );
document.write( "\n" );
document.write( "Using an alternate method, multiply the bottom equation by 4, so the x part cancels out, then add the 2 equations.\r<BR>\n" );
document.write( "\n" );
document.write( "4x - 4x -12y + 12y = 5 - 4<BR>\n" );
document.write( "0 = -1\r<BR>\n" );
document.write( "\n" );
document.write( "The answer I am finding is \"empty set\"<BR>\n" );
document.write( "I am sorry if I am either wrong or if my explanation is unclear.  If it is unclear though just worry about understanding the first part I said. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );