document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930002>Question 930002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	A tire company finds the lifespan for one brand of its tires is normally distributed with a mean of 49,900 miles and a standard deviation of 6000 miles. If the manufacturer is willing to replace less than 10% of the tires, what should be the approximate number of miles for a warranty?\r<BR>\n" );
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document.write( "59,770<BR>\n" );
document.write( "42,220<BR>\n" );
document.write( "40,030<BR>\n" );
document.write( "None of the above<BR>\n" );
document.write( "57,580<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564659 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6000(invNorm(.90)) + 49,900 = 6000(1.28) + 49,900 = 57,580<BR>\n" );
document.write( "top 10% of the tires have more than 57,580mi <BR>\n" );
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