document.write( "Question 929940: The population of a city increases by 4,000 people each year. In 2025 the population is projected to be 450,000 people,. What is the equation that gives the city's population p ( in thousands of people) x years after 2010? \n" ); document.write( "
Algebra.Com's Answer #564585 by TimothyLamb(4379)\"\" \"About 
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population equation (in thousands of people), starting in 2025:
\n" ); document.write( "p = 4x + 450
\n" ); document.write( "to use this equation, x = (year - 2025)
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\n" ); document.write( "find population (in thousands of people), in 2010:
\n" ); document.write( "p(2010) = 4*(2010 - 2025) + 450
\n" ); document.write( "p(2010) = 4*(-15) + 450
\n" ); document.write( "p(2010) = 390
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "---
\n" ); document.write( "population equation (in thousands of people), starting in 2010:
\n" ); document.write( "p = 4x + 390
\n" ); document.write( "to use this equation, x = (year - 2010)
\n" ); document.write( "---
\n" ); document.write( "check the answer:
\n" ); document.write( "by calculating the population (in thousands of people), in the year 2025:
\n" ); document.write( "p = 4x + 390
\n" ); document.write( "x = 2025
\n" ); document.write( "p = 4*(2025 - 2010) + 390
\n" ); document.write( "p = 4*(15) + 390
\n" ); document.write( "p = 450
\n" ); document.write( "---
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