document.write( "Question 929697: A silversmith combined pure silver which cost $8.50 an ounce with 100 oz of a silver alloy which cost $4.00 an ounce. how many ounces of pure silver were used to make an alloy of silver selling for $6.00 an ounce? \n" ); document.write( "
Algebra.Com's Answer #564491 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A silversmith combined pure silver which cost $8.50 an ounce with 100 oz of a silver alloy which cost $4.00 an ounce. \n" ); document.write( " how many ounces of pure silver were used to make an alloy of silver selling for $6.00 an ounce? \n" ); document.write( ": \n" ); document.write( "Let x = amt of pure silver required \n" ); document.write( "The final amt is to be 100 oz, therefore: \n" ); document.write( "(100-x) = amt of alloy \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( "8.5x + 4(100-x) = 6(100) \n" ); document.write( "8.5x + 400 -4x = 600 \n" ); document.write( "8.5x - 4x = 600 - 400 \n" ); document.write( "4.5x = 200 \n" ); document.write( "x = 200/4.5 \n" ); document.write( "x = 44.44 oz of pure silver required \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "See if that checks out. alloy amt = 100 - 44.44 = 55.56 oz \n" ); document.write( "8.5(44.44) + 4(56.56) = 6(100) \n" ); document.write( "377.74 + 222.24 = 599.98 ~ 600 \n" ); document.write( " |