document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=929236>Question 929236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the horizontal asymptote of\r<BR>\n" );
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document.write( "y =(2^2x +2^x -5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #564472 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=564472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the horizontal asymptote of<BR>\n" );
document.write( "y =(2^2x +2^x -5)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=1%2F%282%5E%28-2x%29%29%2B1%2F%282%5E%28-x%29%29-5 ALIGN=MIDDLE  ALT=\"y=1%2F%282%5E%28-2x%29%29%2B1%2F%282%5E%28-x%29%29-5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "as x approaches &#8734;, y approaches -5<BR>\n" );
document.write( "horizontal asymptote=-5<BR>\n" );
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