document.write( "Question 929646: 9 cos ^3 x= 9 cos x \n" ); document.write( "
Algebra.Com's Answer #564467 by lwsshak3(11628)\"\" \"About 
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9 cos ^3 x= 9 cos x [0,2π)
\n" ); document.write( "divide both sides by 9cosx
\n" ); document.write( "cos^2(x)=1
\n" ); document.write( "cosx=±√1=±1
\n" ); document.write( "cosx=1
\n" ); document.write( "x=0
\n" ); document.write( "cosx=-1
\n" ); document.write( "x=π \n" ); document.write( "
\n" );