document.write( "Question 929457: Sally's quiz average in a class is exactly 84. After 5 consecutive scores of 100, her quiz average goes up to exactly 92. How many quiz scores does Sally have after the 5 consecutive 100s? \n" ); document.write( "
Algebra.Com's Answer #564418 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Assuming the quizzes are equally weighted:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let s = # quiz scores before the 5 scores of 100. Then 84s = sum of the scores, and 84s + 5*100 = 84s + 500 = the sum of her scores afterwards.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "She now has s+5 quiz scores, so (84s + 500)/(s+5) = 92. Solving, s = 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another way to see that she had 5 scores beforehand is to note that 92 is exactly halfway between 84 and 100. \n" ); document.write( " |